📄 Exam Questions & Readable Text Transcript
Full OCR-extracted text of questions, syllabus codes, and exam instructions.
Extracted Content: 2018_stas_Alevel_nov_paper2
Page 1
Extracted Text
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A. ZIMBABWE SCHOOL EXAMINAT!O Neel
General Certificate of Education AdY<em>"</em>
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MARKING SCHEME
NOVEMBER 2018
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STATISTICS 6046/2 ye
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Page 2
Extracted Text
9M a) amo mae ° 2, (a2) Any three from the following: - in? i ue 2 oie ie: It allows quicker contact with respondents” ; Bl
2 callbacks can be made if the respondent is not initially available BI
- probing is possible { Clas Ay *f Mate pede psBl
: a larger sample of respondents can be reached in a short stiott Space of 7 eet bs
se time ELE PORG Lee liheop, head
(b) (i) 6 7 8 8 BI
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Bl
Correct 10
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correct
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Key 3/5 means 35 core)
(ii) Original data is preserved ¢ Bl
5 nde > ghieeornan '/s spread {8}
bh ZL tex to pte (Ne +4 A
(a) Tn permutations, order of anangenient is important whilst iri 123 ft order tow —
at 7 combinations, order is not important y P22 weds nh rege
SBE zs a i hes,
6) @ i #. c “4 a Ml
= ~ —3 anw Ba Al
Pe 4 . , -
gq) (ii) Sc, xc, = 5x3 ° “>MI
= 15- > Al
Set 15 lus vabts
» (ii) PQ faulty) = 3 haa vals a V NY
= 0,54 > Al 8]
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esas
BRAS
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Page 3
Extracted Text
(b) (i) (ii) (roy 4)3
pees Pee ¥)
> C4 44-4 &. a 10s
—— pels. ranvh 8
wl a
(hy Ye pret
Cee VEL Soy we onat :
= Or “ee 7, boosh
Bi fr th cone
SS, fe) 46 ab oiith LL
‘, ¥ a
1 Bs “ ,
= 602) 72 pan
G : ) + (: x03) + G 025) uv Mr
= 0,25-
Al
(Joa) = Meg
| peas > Cott pa moeter B
ou5 pA : eM y
i i encig H, iA Ay denon ret DML y
iy 1 ‘ . = hm
~ § rel} Aaa & 3 “SPAL
lel BI valoss
3 he ! 5 ofx
4 10) IT
36 | 36 | 3¢ BI ae
ignites “i ion COMTER
' f BI All
i {af go te | correct
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Page 4
Extracted Text
4 7 * (b) P(Prime) 36 y == Pi 0,4722— BRAS Sgr Bl = +43 xt Ade © @ EO * 2%36 go PASS us ; ° mre Mt = 4,6667 = 4% 6 we 1s 1o Al Gi) vartx) = 4%56 +9 36 TOM SB og bus BY rE” 6 x= ~ (4.6667)? MI = GR go> WO 4 AL (a) fkesdt = 1 [-3ke3] = 1 Cdk Be ( ee ip fan (2 aha ive s 2 bo iL, 3k = aes, and = | ke = , Al ) : [xe dx pe dy =. Leu = x = eds du = dy vos —%eT : F Lede ny & al fc f 3e? dal My eo f wn a ra . = <-xe "3 + Je 3 dx amp 4 (dag hes A, » Jxe"t— 3e-3] Adkanpe +h S wn, zs 3 CAs Day () PX 260) = ff e-tady = [ei] _ Alene 47) 60 i] pact Mead) = e~ 20 or equiv ( es ac anger) Al WY. 2g is) a — he 17 oy | 3 wf oly 4Scanned by CamScanner ;
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Page 5
Extracted Text
() — @) XX Bin (8,09)50U
Px = - 8
&=8 = "ag, bad)" MI
= 0,149
. _ .
(ii) -X ~ Bin (20; 0,9) Sot B
P(x<18) = 1 fhe eta) 4 Poe = 19) + PCE = 2057 Ot Bre Hie,
= 1- [0,28540,27+012) SU! ret
= 0,32 mn
gob
(ii) X~N(180;18) — Correct prarreress Bl
C
PO ¢ 182) = P(X ¢ 1025) -—Aeaep chew =
. p(z< ina 5 pee) $42 yalsed » Mi
= via
‘i = P(2Z < 0.5892)
an
JI— Or SS, ip he _detet 3S Al fl)
a ie - > : bee ! Begg Bante
. i-P 2 “acy fi eo inethod._ , MI
6 @ wr! Seas. ww it .
i2p?+p-1=0 -
J abe gb ke Die sag
(3p + 1)(4p- 1) = 0 ya heen A | .
1 dpe - er
p= 5 P _=
1 ~~ SAl
»peq —
= 1-P% 83)
(ii) POX > 3) :
eo A {PO = 1) + P(x = 2) + Pr = 3))
3 1 2
= 3-H d+ @'y] ————
»
2- * ar {3}
= 0,42 . j ly 3 ; aN a UY LL
er) TOP. Boe
4 64
Sm, &
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Page 6
Extracted Text
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Page 7
Extracted Text
(©)(a)
(b)
= = 0,9576
Al
di There is 9 Very strong negative ay 1 {4}
“ = B(5900)-(1 40714: a
(rv = eran ee Mi-
= -188
AY’
yas M— 5625
~ 9869 = 1880p ~ 4 a= pater MIA! [4]
: TS) Bur Doh Caen gegen”
(ii) (a) When D= 12 1
» M& ~1,99(12 - 17,5) + 56.25
Shh et
ae ff, * 66,59 AS
5 ae ~
(b) Not possibife, it jg out of range — [4 : BIBI [4]
et > _ 1235
@ F = 50455 Qorte re Cette
= 51,235 al
eon (2304 - 2 _ M1
aE: 169 ) we
ee = 0,867 Al
oe
c 33542.17 02
(i) 512358219 ag ”
235 4 0,207 : wey liend
53.235 4 0.202 At ee
@
ai)
X~Po(6) 30 ee B
= PXeo)+PA=N+PR=2)
P(X Ss 2) oss baftebs be
ee
MI
=
e eS +64 18)
A
= 0,0619 -
w= 3B BI
X~Po(3) | ;
ist ee Ml
pX=0) F “a
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Page 8
Extracted Text
= 0,049 ee ae ane 9 (a) a ; L Fi is at lat lytA LENCZ 10067 082). ald Pebecreben CONE Ch 3. ot “Blnye lt th L > 2100 =
abe 2Bk i Pax 0) Sa. ihe: ely PAG 5 M)
wy Of = os ‘Ne Bee cips Rideag c
l me G7, og wil (3]
b
(b) Ply hy... ths ©S, +5. 4. Si) then p @ 36 =Oo%
See
&
+. iy 33,
PLY ~x X09)
‘ ; £
an 4 (roo: scob)* xen rbh, 5 500) = e I: 20055, Bt By
yf - -1L&s PY ~ x 00 awtar pd. ee
(2 > RD = Plage) Shawdarcdcon sn, _
Ss = Pz Gi34ny
-] - 0,098 Boy,
= 04) amy, ecg
= ©8,91/2 ‘ een aaa
- ele DEES = 02a = fSoet ey] ie
as —== ———2> Al {4}
aa) (c) 80 4x) ~n (4300, VE 062) —
j . 55 9 OL >
(21) geese) PC4 250 <¥4X <4 400)
= eo A 8h—4 30 pe .
rip =) hb Legs Ml
. My 17 2
| = P(-0.67 <2 < 1,34) Plesme2 <nseq)
| ‘ “ 0(154) + ©0067) -1 loft > ee
= 0,9099 + 0,7486 —}
= o6ses << Oy bu “ore AY (3]
(4) P(Ler2s7 = P(L — 2850)
L—25 ~ N(~20; 1300) => feapo oe adase as
( ) ( grays 3) ) BIBI
20
99 P(L—- 28720) = ais me) -MI
- me
- P(e = 0,015) - on ——
St
= ~1—-4(0;6547) 05, ian ae ee ;
—Ss
= ~4+-=077102 : “ Mi
02890
it
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Page 9
Extracted Text
; tailed test look: 10 (a) (i) ai tleos fora er me ie or decrease whilst a two tailed ii A Statistic is a meas (ii) from a population Ure from a Sample whilst a parameter is a measure iil A population is the enti am a Eanulation TUTE Broup under study whilst a sample is part of (b) x = 4,978 BX ge= 0.019" + Ae 4 (244 ser 4449 Hg: P= 404 Hy w#S Ge pees 4 4978-5 Tal = “tae We = “347 ~3 616 anne : : ita Spoaioeee Sealey 6, Tess = #555 3,26 pb, CLF S250 fer” 4b pak x ne <3. 355, we reject Ho and conelude its net in good working order. 11 (a) (i) A time series is a set of observations of a random variable in chronological (time) arder, (ii) A trend is a peneral increase or decrease (bye y (i) Sales J point M.A 1, 700 2. 260 Aisi) 3 360 433 4 800 $00 ee | 5 400 566s at. 6. 500 633 aly mae A 7. 1000 666 * esprecd 8 500 700 — 9, 600 766 ge AN cateat 10. 1 200 Ne Cen pee ay There was a general incregse in ales a cvneramenene ye BY B Q.Scanned by CamScanner
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Page 10
Extracted Text
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Page 11
Extracted Text
12Ho: the observations follow a Normal distribution with mean ee Z Bl
Hy: the observations does not follow a Normal distribution wi mean 1637 a
2 Letdnr}é lope ‘
nm E aga) - MIAL pp ene
4 266 =~ 'S €e ga depo
18 1818 ——. of, 4.9 Sa At Fit)
40 36,9 —___ Ase Ve uy”
20 22,8 _ 2, ? > a) oy
3 4,47 Fo,4? Al— All cerf2eb
O E {0-E) Bate BI pooling
Fo A me
- . 4° pAarBv€- ae poten ‘
2 20.8 2yos” 0969 0,173 vas wii
40 36.9 3005 260 7 7
23 232. 9M 0.648 07),
4! 0977 f
.@ fe pe ae a5
Xi = 5am Be)
$9 we accept Ho and cx
nwith a mean of 163
Since 0.977
Nonna] dis
C eH < S35
if
wnctade thar i folfo
ae |
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